已知a b互为相反数,c d互为倒数x的绝对值等于2求x的平方减(a+b+cd)*x+(a+b)2009+(-cd)2010次方



解: a+b=0, cd=1, x=±2
x²-(a+b+cd)x+(a+b)^2009+(-cd)^2010
=4-(0+1)x+0+1
=5-x
①当x=2时,原式=5-2=3
②当x=-2时,原式=5-(-2)=7


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